x^2+240x+3600=0

Solution for x^2+240x+3600=0 equation:

x^2+240x+3600=0

a = 1; b = 240; c = +3600;
Δ = b2-4ac
Δ = 2402-4·1·3600
Δ = 43200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{43200}=\sqrt{14400*3}=\sqrt{14400}*\sqrt{3}=120\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-120\sqrt{3}}{2*1}=\frac{-240-120\sqrt{3}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+120\sqrt{3}}{2*1}=\frac{-240+120\sqrt{3}}{2}
$